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Article ID: 917419 - Last Review: November 20, 2007 - Revision: 1.3
BUG: The datetime data type and the smalldatetime data type are always evaluated by using the us_english language environment when you use the CREATE PARTITION FUNCTION statement in SQL Server 2005
BUG #: 430091 (SQLBUDT)
BUG #: 430965 (SQLBUDT)
BUG #: 432476 (SQLBUDT)
When you use the CREATE PARTITION FUNCTION
statement to create a partition function in Microsoft SQL Server 2005, the
datetime data type and the
smalldatetime data
type are always evaluated by using the us_english language
environment. This problem occurs when the language environment for the SQL Server
2005 session is not set to the us_english language
environment.
Note This problem does not occur when the language environment for
the SQL Server 2005 session is set to
the us_english language
environment.
To work around this problem, use one of the following methods.
Method 1
Use the multilanguage
YYYYMMDD format
for the
datetime data type and for the
smalldatetime data type. For example, use the following code example to work around this problem.
CREATE PARTITION FUNCTION pf (datetime)
AS RANGE RIGHT FOR VALUES ('20051231','20061231');Method 2
Explicitly call the
CONVERT function, and provide a date format style. For example,
use the following code example to work around this problem by using style 104 for the German date
format.
CREATE PARTITION FUNCTION pf (datetime)
AS RANGE RIGHT FOR VALUES (
convert(datetime, '31.12.2005', 104),
convert(datetime, '31.12.2006', 104));
Microsoft has confirmed that this is a bug in the Microsoft products that are
listed in the "Applies to" section.
APPLIES TO
- Microsoft SQL Server 2005 Standard Edition
- Microsoft SQL Server 2005 Standard X64 Edition
- Microsoft SQL Server 2005 Standard Edition for Itanium-based Systems
- Microsoft SQL Server 2005 Enterprise X64 Edition
- Microsoft SQL Server 2005 Enterprise Edition for Itanium-based Systems
- Microsoft SQL Server 2005 Enterprise Edition
- Microsoft SQL Server 2005 Developer Edition
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