Microsoft Knowledge Base Email Alertz

KBAlertz.com: This article shows you how to create a Visual Basic for Applications procedure to open a table, read the data, and find the statistical median. The median is a measure of central tendency, another "middle" of a data set, like the mean or av

Receive Microsoft Knowledge Base articles by E-Mail?

Every night we scan the Microsoft Knowledge Base. If technologies you're interested in are updated, we'll send you an e-mail. You only get one e-mail a day, and only when new articles are added.

Click here to create a
FREE account
Already have an account?
[Click here to Login]

Search KbAlertz

Advanced Search

Webmasters
Put kbAlertz on your website.
[ Click Here for more! ]





ASP.NET 3.5 Web Hosting with Windows 2008 and SQL 2008: Click Here!
Discount ASP.NET Hosting
ASP.NET 2.0 and 3.5
Windows2008 and SQL2008
US and UK Hosting
KBAlertz referrals get
** SIX MONTHS FREE **


Community Site



We Send hundreds of thousands of emails using ASP.NET Email


ASP.NET 3.5 Web Hosting with Windows 2008 and SQL 2008: Click Here!
Discount ASP.NET Hosting
ASP.NET 2.0 and 3.5
Windows2008 and SQL2008
US and UK Hosting
KBAlertz referrals get
** SIX MONTHS FREE **




Mentioned In








Microsoft Knowledge Base Article

This article contents is Microsoft Copyrighted material.
©2005-©2007 Microsoft Corporation. All rights reserved. Terms of Use | Trademarks




Article ID: 95918 - Last Review: January 18, 2007 - Revision: 2.3

ACC: How to Use Code to Derive a Statistical Median

This article was previously published under Q95918
Advanced: Requires expert coding, interoperability, and multiuser skills.

On This Page

SUMMARY

This article shows you how to create a Visual Basic for Applications procedure to open a table, read the data, and find the statistical median. The median is a measure of central tendency, another "middle" of a data set, like the mean or average). The data set consisting of the numbers 1, 2, 3, 6, and 100 has a median of 3, the middle of the set. The data set consisting of the numbers 1, 2, 6, and 10 has a median of 4, the middle of the set [(2 + 6) / 2 = 4].

This article assumes that you are familiar with Visual Basic for Applications and with creating Microsoft Access applications using the programming tools provided with Microsoft Access. For more information about Visual Basic for Applications, please refer to your version of the "Building Applications with Microsoft Access" manual.

NOTE: Visual Basic for Applications is called Access Basic in Microsoft Access versions 1.x and 2.0. For more information about Access Basic, please refer to the "Introduction to Programming" manual in Microsoft Access version 1.x or the "Building Applications" manual in Microsoft Access version 2.0.

MORE INFORMATION

To create a procedure that determines the statistical median of a set of numbers:
  1. Create a module and type the following line in the Declarations section if it is not already there:
    Option Explicit
    					
  2. Type the following procedure:

    NOTE: In the following sample code, an underscore (_) at the end of a line is used as a line-continuation character. Remove the underscore from the end of the line when re-creating this code in Access Basic.
In Microsoft Access 2.0, 7.0, and 97:
    Function Median (tName$, fldName$) As Single
      Dim MedianDB As Database
      Dim ssMedian As Recordset
      Dim RCount%, i%, x%, y%, OffSet%
      Set MedianDB = CurrentDB()
      Set ssMedian = MedianDB.Openrecordset("SELECT [" & fldName$ & _
                "] FROM [" & tName$ & "] WHERE [" & fldName$ & "] IS _
                NOT NULL ORDER BY [" & fldName$  & "];")
      'NOTE: To include nulls when calculating the median value, omit
      'WHERE [" & fldName$ & "] IS NOT NULL from the example.
				
      ssMedian.MoveLast
      RCount% = ssMedian.RecordCount
      x% = RCount% Mod 2
      If x% <> 0 Then
         OffSet% = ((RCount% + 1) / 2) - 2
         For i% = 0 To OffSet%
            ssMedian.MovePrevious
         Next i
         Median = ssMedian(fldName$)
      Else
         OffSet% = (RCount% / 2) - 2
         For i% = 0 To OffSet%
            ssMedian.MovePrevious
         Next i
         x% = ssMedian(fldName$)
         ssMedian.MovePrevious
         y% = ssMedian(fldName$)
         Median = (x% + y%) / 2
      End If
      ssMedian.Close
      MedianDB.Close
    End Function
				
In Microsoft Access 1.x:
    Function Median (tName$, fldName$) As Single
      Dim MedianDB As Database
      Dim ssMedian As Snapshot
      Dim RCount%, i%, x%, y%, OffSet%
      Set MedianDB = CurrentDB()
      Set ssMedian = MedianDB.CreateSnapshot("SELECT [" & fldName$ & _
                "] FROM [" & tName$ & "] WHERE [" & fldName$ & "] IS _
                NOT NULL ORDER BY [" & fldName$  & "];")
      'NOTE: To include nulls when calculating the median value, omit
      'WHERE [" & fldName$ & "] IS NOT NULL from the example.
      ssMedian.MoveLast
      RCount% = ssMedian.RecordCount
      x% = RCount% Mod 2
      If x% <> 0 Then
         OffSet% = ((RCount% + 1) / 2) - 2
         For i% = 0 To OffSet%
            ssMedian.MovePrevious
         Next i
         Median = ssMedian(fldName$)
      Else
         OffSet% = (RCount% / 2) - 2
         For i% = 0 To OffSet%
            ssMedian.MovePrevious
         Next i
         x% = ssMedian(fldName$)
         ssMedian.MovePrevious
         y% = ssMedian(fldName$)
         Median = (x% + y%) / 2
      End If
      ssMedian.Close
      MedianDB.Close
    End Function
				

How to Use the Median() Function

Create a form and add a text box control where you want to display the median values of a data set. Set the ControlSource property of the text box control to the following:
=Median("<TableName>", "<FieldName>")
				
The value of this control is the median of the data set. Another way to use this function is to call it from within another function that compares the median from different data sets. For example,
   Function CompareMedians()
      Dim MyDB as Database
      .
      .
      .
      X = Median("<TableName>", "<FieldName>")
      Y = Median("<TableName>", "<FieldName>")
      If X > Y Then Debug.Print "The median for X is greatest."
   End Function
				

APPLIES TO
  • Microsoft Access 1.0 Standard Edition
  • Microsoft Access 1.1 Standard Edition
  • Microsoft Access 2.0 Standard Edition
  • Microsoft Access 95 Standard Edition
  • Microsoft Access 97 Standard Edition
Keywords: 
kbhowto kbprogramming KB95918
Retired KB ArticleRetired KB Content Disclaimer
This article was written about products for which Microsoft no longer offers support. Therefore, this article is offered "as is" and will no longer be updated.
       

Community Feedback System

Very often, it takes hours to solve a problem. Very often, you've looked high and low, and have tried a lot of solutions. When you finally found it, chances are, it was because someone else helped you. Here's your chance to give back. Use our community feedback tool to let others know what worked for you and what didn't.

Please also understand that the community feedback system is not warranted to be correct, it's simply a system that we've built to let people try and help each other. If something in a feedback response doesn't make sense to you, or you're not comfortable making changes that the feedback talks about (like registry edits), please consult a professional.

Thank you for using kbAlertz.com Feedback System.

-- Scott Cate

Be the first to leave feedback, to help others about this knowledge base article.

(Optional) Name

(Optional) Public URL Or Email

Comments
No HTML -- Text Only Please